Find even and odd component of the signal x(t)=(1+t3) cos(10t).
Given,
x(t)=(1+t3) cos(10t)
x(-t)=(1-t3) cos(10t)
Even component=(x(t)+x(-t))/2
=( (1+t3) cos(10t) + (1-t3)
cos(10t))/2
=(cos(10t)+ t3cos(10t)+
cos(10t)-t3cos(10t))/2
=cos(10t)
Odd component=(x(t)-x(-t))/2
=( (1+t3) cos(10t) - (1-t3)
cos(10t))/2
=t3cos(10t)
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